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In an ammeter 0.5% of main current passes through galvanometer; If resistance of galvanometer is G, the resistance of ammeter will be. -

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Question

In an ammeter 0.5% of main current passes through galvanometer; If resistance of galvanometer is G, the resistance of ammeter will be.

Options

  • G/200

  • G/199

  • 199 G

  • 200 G

MCQ

Solution

G/199

Explanation:

Here Ig = 0.5% of I = 0.005 I

Is = I – Ig = 1 – 0.005 I = 0.995 I

S = `(IgG)/(Is) = (0.0051 xx G)/0.9951 = G/199`

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