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प्रश्न
Why do compounds having similar geometry have different magnetic moment?
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उत्तर
It is due to the presence of weak and strong ligands in complexes, if \[\ce{CFSE}\] is high, the complex will show low value of magnetic moment and vice versa, e.g. \[\ce{[CoF6]^{3-}}\] and \[\ce{[Co(NH3)6]^{3+}}\], the former is paramagnetic and the latter is diamagnetic.
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संबंधित प्रश्न
Write the hybridization and magnetic behaviour of the complex [Ni(CO)4].
(At.no. of Ni = 28)
Write the hybridization and shape of the following complexe : [CoF6]3–
(Atomic number : Co = 27, Ni = 28)
Write the hybridization and shape of the following complexe : [Ni(CN)4]2–
(Atomic number : Co = 27, Ni = 28)
[NiCl4]2− is paramagnetic while [Ni(CO)4] is diamagnetic though both are tetrahedral. Why?
Explain [Co(NH3)6]3+ is an inner orbital complex, whereas [Ni(NH3)6]2+ is an outer orbital complex.
[At. No.: Co = 27, Ni = 28]
Write down the IUPAC name of the following complex and indicate the oxidation state, electronic configuration and coordination number. Also, give the stereochemistry and magnetic moment of the complex:
K[Cr(H2O)2(C2O4)2].3H2O
Amongst the following ions, which one has the highest magnetic moment value?
Write the hybridisation and magnetic character of [Co(C2O4)3]3–.
(At. no. of Co = 27)
Write the hybridization type and magnetic behaviour of the complex [Ni(CN)4]2−. (Atomic number of Ni = 28)
Write the hybridization and magnetic character of the following complexes:
[Fe(H2O)6]2+
(Atomic no. of Fe = 26)
Which of the following options are correct for \[\ce{[Fe(CN)6]^{3-}}\] complex?
(i) d2sp3 hybridisation
(ii) sp3d2 hybridisation
(iii) paramagnetic
(iv) diamagnetic
Explain why \[\ce{[Fe(H2O)6]^{3+}}\] has magnetic moment value of 5.92 BM whereas \[\ce{[Fe(CN)6]^{3-}}\] – has a value of only 1.74 BM.
Assertion: \[\ce{[Fe(CN)6]^{3-}}\] ion shows magnetic moment corresponding to two unpaired electrons.
Reason: Because it has d2sp3 type hybridisation.
[Ti(H2O6]3+ T is paramagnetic is nature due to
The correct order of magnetic moment (spin only value in B.m.) is:
