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Why do compounds having similar geometry have different magnetic moment?

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प्रश्न

Why do compounds having similar geometry have different magnetic moment?

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उत्तर

It is due to the presence of weak and strong ligands in complexes, if \[\ce{CFSE}\] is high, the complex will show low value of magnetic moment and vice versa, e.g. \[\ce{[CoF6]^{3-}}\] and \[\ce{[Co(NH3)6]^{3+}}\], the former is paramagnetic and the latter is diamagnetic.

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अध्याय 9: Coordination Compounds - Exercises [पृष्ठ १२४]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
अध्याय 9 Coordination Compounds
Exercises | Q III. 33. | पृष्ठ १२४

संबंधित प्रश्न

For the complex [Fe(H2O)6]+3, write the hybridisation, magnetic character and spin of the complex. (At, number : Fe = 26)


For the complex [Fe(CN)6]3–, write the hybridization type, magnetic character and spin nature of the complex. (At. number : Fe = 26).


Write the hybridization and magnetic behaviour of the complex [Ni(CO)4].

(At.no. of Ni = 28)


Write the hybridization and shape of the following complexe : [CoF6]3–

(Atomic number : Co = 27, Ni = 28)


[NiCl4]2− is paramagnetic while [Ni(CO)4] is diamagnetic though both are tetrahedral. Why?


[Fe(H2O)6]3+ is strongly paramagnetic whereas [Fe(CN)6]3− is weakly paramagnetic. Explain.


Explain [Co(NH3)6]3+ is an inner orbital complex, whereas [Ni(NH3)6]2+ is an outer orbital complex.

[At. No.: Co = 27, Ni = 28]


Write the hybridisation and magnetic character of [Co(C2O4)3]3–.

(At. no. of Co = 27)


Why is [NiCl4]2− paramagnetic while [Ni(CN)4]2− is diamagnetic? (Atomic number of Ni = 28)


Write the hybridization and magnetic character of the following complexes:
[Fe(H2O)6]2+
(Atomic no. of Fe = 26)


Write the hybridization and magnetic character of the following complexes:
[Fe(CO)5]
(Atomic no. of Fe = 26)


Which of the following options are correct for \[\ce{[Fe(CN)6]^{3-}}\] complex?

(i) d2sp3 hybridisation

(ii) sp3d2 hybridisation

(iii) paramagnetic

(iv) diamagnetic


Explain why \[\ce{[Fe(H2O)6]^{3+}}\] has magnetic moment value of 5.92 BM whereas \[\ce{[Fe(CN)6]^{3-}}\] – has a value of only 1.74 BM.


Assertion: \[\ce{[Fe(CN)6]^{3-}}\] ion shows magnetic moment corresponding to two unpaired electrons.

Reason: Because it has d2sp3 type hybridisation.


[Ti(H2O6]3+ T is paramagnetic is nature due to


The correct order of magnetic moment (spin only value in B.m.) is:


Explain [Fe(CN)6]3− is an inner orbital complex, whereas [FeF6]3− is an outer orbital complex.

[Atomic number: Fe = 26]


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