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प्रश्न
Which of the following alkyl halides will undergo SN1 reaction most readily?
विकल्प
\[\ce{(CH3)3C-F}\]
\[\ce{(CH3)3C-Cl}\]
\[\ce{(CH3)3C-Br}\]
\[\ce{(CH3)3C-I}\]
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उत्तर
\[\ce{(CH3)3C-I}\]
Explanation:
\[\ce{(CH3)3C-I}\] will undergo SN1 reaction most readily as C-I bond is weakest, due to the large difference in the size of carbon and iodine.
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संबंधित प्रश्न
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| I | II | III | IV |
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Nucleophilic Substitution: Influences of solvent polarity: The reaction rate (SN2) of 2-bromopropane and NaOH in ethanol containing 40% water is twice slower than in absolute ethanol. Hence the level of solvent polarity has an influence on both SN1 and SN2 reactions but with different results. Generally speaking, a weak polar solvent is favourable for SN2 reaction, while a strong polar solvent is favourable for SN1. Generally speaking, the substitution reaction of tertiary haloalkane is based on SN1 mechanism in solvents with a strong polarity (for example ethanol containing water). |
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(ii)

OR
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