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The vernier scale of a travelling microscope has 50 divisions which coincide with 49 main scale divisions.

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प्रश्न

The vernier scale of a travelling microscope has 50 divisions which coincide with 49 main scale divisions. If each main scale division is 0.5 mm, calculate the minimum inaccuracy in the measurement of distance.

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उत्तर

A Diagram of the vernier calliper is shown below.


According to the problem, 50 divisions of the Vernier scale coincide with 49 main scale divisions.

50 VSD = 49 MSD

⇒ 1 MSD = `50/49` VSD or 1 VSD = `49/50` MSD

Where MSD = Main scale division and VSD = Vernier scale division.

We know that

Minimum inaccuracy = Vernier constant

= 1 MSD – 1 VSD

= 1 MSD – `49/50` MSD = `1/50` MSD

It is given in the problem that 1 MSD = 0.5 mm

Hence, minimum inaccuracy = `1/50 xx 0.5` mm = `1/100` = 0.01 mm

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अध्याय 2: Units and Measurements - Exercises [पृष्ठ ९]

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एनसीईआरटी एक्झांप्लर Physics [English] Class 11
अध्याय 2 Units and Measurements
Exercises | Q 2.28 | पृष्ठ ९

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