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You measure two quantities as A = 1.0 m ± 0.2 m, B = 2.0 m ± 0.2 m. We should report correct value for AB as ______. - Physics

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प्रश्न

You measure two quantities as A = 1.0 m ± 0.2 m, B = 2.0 m ± 0.2 m. We should report correct value for `sqrt(AB)` as ______.

विकल्प

  • 1.4 m ± 0.4 m

  • 1.41 m ± 0.15 m

  • 1.4 m ± 0.3 m

  • 1.4 m ± 0.2 m

MCQ
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उत्तर

You measure two quantities as A = 1.0 m ± 0.2 m, B = 2.0 m ± 0.2 m. We should report correct value for `sqrt(AB)` as 1.4 m ± 0.2 m.

Explanation:

When we take significant figures of measured quantities, we also include zeros in significant figures. Here quantities A and b are the measuring quantities thus the number of significant figures in 1.0 m and 2.0 m is two.

`sqrt(AB) = sqrt(1.0 xx 2.0)`

= `sqrt(2)`

= 1.414 m

Here the minimal significant figure is two in the significant figures, 1.0 m and 2.0 n. Thus,

`x = sqrt(AB)` = 1.4

`(Δx)/x = 1/2 [(ΔA)/A + (ΔB)/B]`

= `1/2 0.2 [1/1.0 + 1/2.0]`

= `0.1 [(2.0 + 1.0)/(1.0 + 2.0)]`

`(Δx)/1.4 = 0.1 (3.0/2.0)`

= 2.1 m

`Δx` = 0.2 m rounding to one place of decimal.

∴ `sqrt(AB) = (1.4 +- 0.2)` m.

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अध्याय 2: Units and Measurements - Exercises [पृष्ठ ६]

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एनसीईआरटी एक्झांप्लर Physics [English] Class 11
अध्याय 2 Units and Measurements
Exercises | Q 2.8 | पृष्ठ ६

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