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The Third Term of an A.P. is 7 and the Seventh Term Exceeds Three Times the Third Term by 2. Find the First Term, the Common Difference and the Sum of First 20 Terms.

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प्रश्न

The third term of an A.P. is 7 and the seventh term exceeds three times the third term by 2. Find the first term, the common difference and the sum of first 20 terms.

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उत्तर

\[\text { Given }: \]

\[ a_3 = 7, a_7 - 3 a_3 = 2\]

\[\text { We have: } \]

\[ a_3 = 7\]

\[ \Rightarrow a + \left( 3 - 1 \right)d = 7\]

\[ \Rightarrow a + 2d = 7 . . . (i) \]

\[\text { Also }, a_7 - 3 a_3 = 2\]

\[ \Rightarrow a_7 - 21 = 2 (\text { Given })\]

\[ \Rightarrow a + \left( 7 - 1 \right)d = 23\]

\[ \Rightarrow a + 6d = 23 . . . (ii)\]

\[\text { From (i) and (ii), we get: } \]

\[4d = 16\]

\[ \Rightarrow d = 4\]

\[\text { Putting the value in (i), we get }: \]

\[ a + 2(4) = 7\]

\[ \Rightarrow a = - 1\]

\[ \therefore S_{20} = \frac{20}{2}\left[ 2\left( - 1 \right) + \left( 20 - 1 \right)(4) \right]\]

\[ \Rightarrow S_{20} = 10\left[ - 2 + 76 \right]\]

\[ \Rightarrow S_{20} = 10\left[ 74 \right] = 740\]

\[ \therefore a = - 1, d = 4, S_{20} = 740\]

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अध्याय 19: Arithmetic Progression - Exercise 19.4 [पृष्ठ ३१]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 19 Arithmetic Progression
Exercise 19.4 | Q 18 | पृष्ठ ३१

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