Question

The figure shows an electrolyte of AgCl through which a current is passed. It is observed that 2.68 g of silver is deposited in 10 minutes on the cathode. Find the heat developed in the 20 Ω resistor during this period. Atomic weight of silver is 107.9 g/mol⁻¹.

Answer 1

Given:-

Mass of silver deposited, m = 2.68 g

Time, t = 10 minutes = 600 s

Using the formula, m = Zit, we get:-

\[2 . 68 \times {10}^{- 3} = \frac{107 . 9 \times {10}^{- 3}}{96500} \times i \times 600\]

\[ \Rightarrow i = \frac{2 . 68 \times 96500}{107 . 9 \times 600}\]

\[ \Rightarrow i = 3 . 99 = 4 A\]

Heat developed in the 20 Ω resistor,

\[H =  i^2 Rt\]

\[ \Rightarrow H =  \left( 4 \right)^2  \times 20 \times 600\]

\[ \Rightarrow H = 192000  J = 192  kJ\]