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The conductivity of sodium chloride at 298 K has been determined at different concentrations and the results are given below: Concentration/M 0.001 0.010 0.020 0.050 0.100 10^2 × κ/S m−1 1.237 11.85

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प्रश्न

The conductivity of sodium chloride at 298 K has been determined at different concentrations and the results are given below:

Concentration/M 0.001 0.010 0.020 0.050 0.100
102 × κ/S m−1 1.237 11.85 23.15 55.53 106.74

Calculate ∧m for all concentrations and draw a plot between ∧m and c1/2. Find the value of `Lambda_m^0`.

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संख्यात्मक
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उत्तर

Concentration (M) C1/2
(M1/2)
κ(S m−1) κ(S cm−1) Λm = `bb((kappa xx 1000)/M)` (S cm2 mol−1)
0.001 0.032 1.237 × 10−2 1.237 × 10−4

`(1.237 xx 10^-4 xx 1000)/0.001` = 123.7

0.010 0.100 11.85 × 10−2 11.85 × 10−4 `(11.85 xx 10^-4 xx 1000)/(0.010)` = 118.5
0.020 0.141 23.15 × 10−2 23.15 × 10−4 `(23.15 xx 10^-4 xx 1000)/0.020` = 115.8
0.050 0.224 55.53 × 10−2 55.53 × 10−4 `(55.53 xx 10^-4 xx 1000)/(0.050)` = 111.1
0.100 0.316 106.74 × 10−2 106.74 × 10−4 `(106.74 xx 10^-4 xx 1000)/(0.100)` = 106.7

When the straight line is drawn backwards, it meets the ∧m axis at 124.0 S cm2 mol−1, which is the value of `Lambda_m^0`.

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अध्याय 2: Electrochemistry - Exercises [पृष्ठ ६०]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
अध्याय 2 Electrochemistry
Exercises | Q 2.10 | पृष्ठ ६०
नूतन Chemistry [English] Class 12 ISC
अध्याय 2 Electrochemistry
'NCERT TEXT-BOOK' Exercises | Q 3.10 | पृष्ठ २१०

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