Advertisements
Advertisements
प्रश्न
Advertisements
उत्तर
\[\int \left( a \tan x + b \cot x \right)^2 dx\]
\[ = \int\left( a^2 \tan^2 x + b^2 \cot^2 x +\text{ 2ab tan x }\cot x \right)dx\]
\[ = a^2 \int \tan^2\text{ x dx }+ b^2 \int \cot^2 \text{x dx }+ \text{2ab ∫ dx}\]
\[ = a^2 \int\left( \sec^2 x - 1 \right)dx + b^2 \int\left( {cosec}^2 x - 1 \right)dx + 2ab\ ∫ dx\]
\[ = a^2 \left[ \tan x - x \right] + b^2 \left[ - \cot x - x \right] + \text{2ab x }+ C\]
\[ = a^2 \tan x - b^2 \cot x - \left( a^2 + b^2 - 2ab \right)x + C\]
APPEARS IN
संबंधित प्रश्न
\[\int\left\{ x^2 + e^{\log x}+ \left( \frac{e}{2} \right)^x \right\} dx\]
` = ∫ root (3){ cos^2 x} sin x dx `
The primitive of the function \[f\left( x \right) = \left( 1 - \frac{1}{x^2} \right) a^{x + \frac{1}{x}} , a > 0\text{ is}\]
\[\int\text{ cos x cos 2x cos 3x dx}\]
