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∫ 1 a 2 X 2 − B 2 D X - Mathematics

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प्रश्न

` ∫  {1}/{a^2 x^2- b^2}dx`
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उत्तर

\[\int\frac{dx}{a^2 x^2 - b^2} \]
\[ = \frac{1}{a^2}\int\frac{dx}{x^2 - \left( \frac{b}{a} \right)^2}\]
\[ = \frac{1}{a^2} \times \frac{1}{2\frac{b}{a}} \log \left| \frac{x - \frac{b}{a}}{x + \frac{b}{a}} \right| + C \left[ \therefore \int\frac{dx}{x^2 - a^2} = \frac{1}{2a} \log \left| \frac{x - a}{x + a} \right| + C \right]\]
` = \text{1}/{2ab} \text{ log }\| \frac{ax - b}{ax + b}| + C `

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अध्याय 19: Indefinite Integrals - Exercise 19.14 [पृष्ठ ८३]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 19 Indefinite Integrals
Exercise 19.14 | Q 2 | पृष्ठ ८३

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