Advertisements
Advertisements
प्रश्न
Advertisements
उत्तर
` f (x) = \sqrtx + 1/ \sqrtx `.
integrating both sides
\[\int{f}\left( x \right)dx = \int\left( \sqrt{x} + \frac{1}{\sqrt{x}} \right)dx\]
\[ = \int\left( x^\frac{1}{2} + x^{- \frac{1}{2}} \right)dx\]
\[ = \left[ \frac{x^\frac{1}{2} + 1}{\frac{1}{2} + 1} \right] + \left[ \frac{x^{- \frac{1}{2} + 1}}{- \frac{1}{2} + 1} \right] + C\]
\[ = \frac{2}{3} x^\frac{3}{2} + 2 x^\frac{1}{2} + C\]
APPEARS IN
संबंधित प्रश्न
` ∫ {x-3} /{ x^2 + 2x - 4 } dx `
Write the anti-derivative of \[\left( 3\sqrt{x} + \frac{1}{\sqrt{x}} \right) .\]
If \[\int\frac{\sin^8 x - \cos^8 x}{1 - 2 \sin^2 x \cos^2 x} dx\]
If \[\int\frac{1}{\left( x + 2 \right)\left( x^2 + 1 \right)}dx = a\log\left| 1 + x^2 \right| + b \tan^{- 1} x + \frac{1}{5}\log\left| x + 2 \right| + C,\] then
\[\int\frac{3x + 1}{\sqrt{5 - 2x - x^2}} \text{ dx }\]
\[\int\frac{x + 3}{\left( x + 4 \right)^2} e^x dx =\]
