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प्रश्न

\[\int\frac{1}{\sqrt{x}}\left( 1 + \frac{1}{x} \right) dx\]
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उत्तर

\[\int\frac{1}{\sqrt{x}}\left( 1 + \frac{1}{x} \right)dx\]
\[ = \int x^{- \frac{1}{2}} \left( 1 + \frac{1}{x} \right)dx\]
\[ = \int\left( x^{- \frac{1}{2}} + \frac{1}{x^\frac{3}{2}} \right)dx\]
\[ = \int x^{- \frac{1}{2}} dx + \int x^{- \frac{3}{2}} dx\]
\[ = \left[ \frac{x^{- \frac{1}{2} + 1}}{- \frac{1}{2} + 1} \right] + \left[ \frac{x^{- \frac{3}{2} + 1}}{- \frac{3}{2} + 1} \right]\]
\[ = 2\sqrt{x} - \frac{2}{\sqrt{x}} + C\]

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अध्याय 19: Indefinite Integrals - Exercise 19.02 [पृष्ठ १४]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 19 Indefinite Integrals
Exercise 19.02 | Q 11 | पृष्ठ १४

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