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Suppose a Monochromatic X-ray Beam of Wavelength 100 Pm is Sent Through a Young'S Double Slit and the Interference Pattern is Observed on a Photographic Plate Placed 40 Cm Away from the Slit.

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प्रश्न

Suppose a monochromatic X-ray beam of wavelength 100 pm is sent through a Young's double slit and the interference pattern is observed on a photographic plate placed 40 cm away from the slit. What should be the separation between the slits so that the successive maxima on the screen are separated by a distance of 0.1 mm?

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उत्तर

Given:

`lambda = 10  "pm" = 100 xx 10^-12  "m"`

`D = 40  "cm" = 40 xx 10^-2  "m"`

`β = 0.1  "mm" = 0.1 xx 10^-3  "m"`

`β = (lambdaD)/d`

`d = (lambdaD)/β`

= `(100 xx 10^-12 xx 40 xx 10^-2)/(10^-3 xx 0.1)`

= `4 xx 10^-7  "m"`

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अध्याय 44: X-rays - Exercises [पृष्ठ ३९६]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 44 X-rays
Exercises | Q 27 | पृष्ठ ३९६

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