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प्रश्न
State Fleming’s right-hand rule.
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उत्तर
Fleming’s right-hand rule:-
Stretch the thumb, forefinger and middle finger of the right hand so that they are perpendicular to each other. If the forefinger indicates the direction of the magnetic field and the thumb shows the direction of motion of the conductor, then the middle finger will show the direction of the induced current.
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संबंधित प्रश्न
Electric field intensity in free space at a distance ‘r’ outside the charged conducting sphere of radius ‘R’ in terms of surface charge density ‘ a ’ is............................
(a)`sigma / in_0[R/r]^2`
(b)`in_0/sigma[R/r]^2`
(c)`R/r[sigma/in_0]^2`
(d)`R/sigma[r/in_0]^2`
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B = − B0 k (r ≤ a; a < R)
= 0 (otherwise)
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(c) the resistivity of the wire of the coil
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State Fleming’s Right Hand Rule.
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- State your observation when the current is switched on.
- Give an explanation for your observation in (i).
- State the rule, which will help you to find the motion of rotation of the coil.
- In which position will the coil ultimately come to rest?
- State four ways of increasing the magnitude of force acting on the coil.
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Write the two names in the following diagram.
Fleming’s right hand rule.
Establish the fact that the relative motion between the coil and the magnet induces an emf in the coil of a closed circuit.
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Will there be any change in the momentary deflection in the galvanometer if number of turns in the coil is increased and a more stronger magnet is moved towards the coil?
OR
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(Round off to two decimal places.)
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