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A Transformer Has 400 Turns in the Primary Winding and 10 Turns in the Secondary Winding. the Primary E.M.F. is 250 V and the Primary Current is 2.0 A. Calculate: - Physics

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प्रश्न

A transformer has 400 turns in the primary winding and 10 turns in the secondary winding. The primary e.m.f. is 250 V and the primary current is 2.0 A. calculate:
(a) The secondary voltage,
(b) The secondary current, assuming 100% efficiency.

संख्यात्मक
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उत्तर

Since, the number of turns in the primary is more than the no. of turns in the secondary it is a step-down transformer.

Given, NP= 400, Ns = 10, EP=250 V, IP= 2A

(a) Let Es be the secondary voltage.

We know that for transformer turn ratio `"N"_"s"/"N"_"p" = "I"_"p"/"I"_"s" = "E"_"s"/"E"_"P"`

E= `"N"_"s"/"N"_"P" xx "E"_"P" = 10/400 xx 250 = 6.25 "V"`

(b) Let Is be the current though secondary

We know that for transformer turn ratio `"N"_"s"/"N"_"P" = "I"_"P"/"I"_"s"`

I = `400/10 xx 2= 80 "A"`

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अध्याय 4: Current Electricity - Exercise 9 [पृष्ठ २१७]

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फ्रैंक Physics - Part 2 [English] Class 10 ICSE
अध्याय 4 Current Electricity
Exercise 9 | Q 1 | पृष्ठ २१७

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