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Prove the following: cot 4x (sin 5x + sin 3x) = cot x (sin 5x – sin 3x)

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प्रश्न

Prove the following:

cot 4x (sin 5x + sin 3x) = cot x (sin 5x – sin 3x) 

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उत्तर

L.H.S. = cot 4x (sin 5x + sin 3x)

= cot 4x × 2sin `(5x + 3x)/2  cos  (5x - 3x)/2`

[∵ sin C + sinD = 2sin `(C + D)/2 cos  (C - D)/2`]

= 2 `(cos4x)/(sin4x) sin 4x cos x`

= 2 cos 4x cos x

R.H.S. = cot x (sin 5x - sin 3x)

= `(cosx)/(sinx) xx 2 sin x cos 4x`

= 2 cos x cos 4x

Hence L.H.S. = R.H.S.

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अध्याय 3: Trigonometric Functions - EXERCISE 3.3 [पृष्ठ ६७]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 3 Trigonometric Functions
EXERCISE 3.3 | Q 15. | पृष्ठ ६७

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