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प्रश्न
Prove that the common chord of two intersecting circles is bisected at right angles by the line of centres.
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उत्तर
Given: Two interesting circles with centres C &D.
AB is their common chord.
To prove: AB bisected by CD at right angles.
Proof : CA = CB ...(radii)
∴ C lies on the right bisector of AB.
Similarly, D lies on the right bisector of AB.
Therefore, CD is the right bisector of AB.
Hence proved.
संबंधित प्रश्न
In each of the given figures; PA = PB and QA = QB.
| i. |  |
| ii. |  |
Prove, in each case, that PQ (produce, if required) is perpendicular bisector of AB. Hence, state the locus of the points equidistant from two given fixed points.
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