Advertisements
Advertisements
प्रश्न
Describe the locus of a point in rhombus ABCD, so that it is equidistant from
- AB and BC;
- B and D.
Advertisements
उत्तर
i.
The locus of the point in a rhombus ABCD which is equidistant from AB and BC will be the diagonal BD.
ii.
The locus of the point in a rhombus ABCD which is equidistant from B and D will be the diagonal AC.
संबंधित प्रश्न
The given figure shows a triangle ABC in which AD bisects angle BAC. EG is perpendicular bisector of side AB which intersects AD at point F.
Prove that:
F is equidistant from AB and AC.
Describe the locus of the centre of a wheel of a bicycle going straight along a level road.
Describe the locus of points inside a circle and equidistant from two fixed points on the circumference of the circle.
Describe the locus of the centres of all circles passing through two fixed points.
By actual drawing obtain the points equidistant from lines m and n; and 6 cm from a point P, where P is 2 cm above m, m is parallel to n and m is 6 cm above n.
In a quadrilateral PQRS, if the bisectors of ∠ SPQ and ∠ PQR meet at O, prove that O is equidistant from PS and QR.
In a quadrilateral ABCD, if the perpendicular bisectors of AB and AD meet at P, then prove that BP = DP.
Prove that the common chord of two intersecting circles is bisected at right angles by the line of centres.
Show that the locus of the centres of all circles passing through two given points A and B, is the perpendicular bisector of the line segment AB.
ΔPBC, ΔQBC and ΔRBC are three isosceles triangles on the same base BC. Show that P, Q and R are collinear.
