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प्रश्न
Describe the locus of a point in rhombus ABCD, so that it is equidistant from
- AB and BC;
- B and D.
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उत्तर
i.
The locus of the point in a rhombus ABCD which is equidistant from AB and BC will be the diagonal BD.
ii.
The locus of the point in a rhombus ABCD which is equidistant from B and D will be the diagonal AC.
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संबंधित प्रश्न
Use ruler and compasses only for this question.
- Construct ΔABC, where AB = 3.5 cm, BC = 6 cm and ∠ABC = 60°.
- Construct the locus of points inside the triangle which are equidistant from BA and BC.
- Construct the locus of points inside the triangle which are equidistant from B and C.
- Mark the point P which is equidistant from AB, BC and also equidistant from B and C. Measure and record the length of PB.
The given figure shows a triangle ABC in which AD bisects angle BAC. EG is perpendicular bisector of side AB which intersects AD at point F.
Prove that:
F is equidistant from A and B.
Draw a line AB = 6 cm. Draw the locus of all the points which are equidistant from A and B.
In the figure given below, find a point P on CD equidistant from points A and B.
Describe the locus of points at a distance 2 cm from a fixed line.
Describe the locus of a stone dropped from the top of a tower.
Draw a triangle ABC in which AB = 6 cm, BC = 4.5 cm and AC = 5 cm. Draw and label:
- the locus of the centres of all circles which touch AB and AC,
- the locus of the centres of all the circles of radius 2 cm which touch AB.
Hence, construct the circle of radius 2 cm which touches AB and AC .
In Fig. ABCD is a quadrilateral in which AB = BC. E is the point of intersection of the right bisectors of AD and CD. Prove that BE bisects ∠ABC.
Find the locus of the centre of a circle of radius r touching externally a circle of radius R.
In Fig. AB = AC, BD and CE are the bisectors of ∠ABC and ∠ACB respectively such that BD and CE intersect each other at O. AO produced meets BC at F. Prove that AF is the right bisector of BC.
