हिंदी

Find the Locus of the Centre of a Circle of Radius R Touching Externally a Circle of Radius R.

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प्रश्न

Find the locus of the centre of a circle of radius r touching externally a circle of radius R.

योग
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उत्तर

Let a circle of radius r (with centre B) touch a circle of radius R at C. Then ACB is a straight line and
AB = AC + CB = R + r

Thus, B moves such that its distance from fixed point. A remains constant and is equal to R + r.
Hence, the locus of B is a circle whose centre is A and radius equal to R + r.

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अध्याय 17: Loci - Figure Based Questions

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आर.एस. अग्रवाल Mathematics [English] Class 10 ICSE
अध्याय 17 Loci
Figure Based Questions | Q 9

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

In each of the given figures; PA = PB and QA = QB. 

i.
ii.

Prove, in each case, that PQ (produce, if required) is perpendicular bisector of AB. Hence, state the locus of the points equidistant from two given fixed points.


In triangle LMN, bisectors of interior angles at L and N intersect each other at point A. Prove that:

  1. Point A is equidistant from all the three sides of the triangle.
  2. AM bisects angle LMN. 

Use ruler and compasses only for this question.

  1. Construct ΔABC, where AB = 3.5 cm, BC = 6 cm and ∠ABC = 60°.
  2. Construct the locus of points inside the triangle which are equidistant from BA and BC.
  3. Construct the locus of points inside the triangle which are equidistant from B and C.
  4. Mark the point P which is equidistant from AB, BC and also equidistant from B and C. Measure and record the length of PB.

Draw an ∠ABC = 60°, having AB = 4.6 cm and BC = 5 cm. Find a point P equidistant from AB and BC; and also equidistant from A and B. 


Describe the locus of the door handle, as the door opens.


Describe the locus of points at distances greater than 4 cm from a given point. 


Describe the locus of points at distances greater than or equal to 35 mm from a given point. 


In a quadrilateral PQRS, if the bisectors of ∠ SPQ and ∠ PQR meet at O, prove that O is equidistant from PS and QR. 


In a quadrilateral ABCD, if the perpendicular bisectors of AB and AD meet at P, then prove that BP = DP. 


ΔPBC and ΔQBC are two isosceles triangles on the same base. Show that the line PQ is bisector of BC and is perpendicular to BC.


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