हिंदी

Describe the Locus for Questions 1 to 13 Given Below: 1. the Locus of a Point at a Distant 3 Cm from a Fixed Point.

Advertisements
Advertisements

प्रश्न

Describe the locus for questions 1 to 13 given below:
1. The locus of a point at a distant 3 cm from a fixed point. 

Advertisements

उत्तर

  

The locus of a point which is 3 cm away from a fixed point is circumference of a circle whose radius is 3 cm and the fixed point is the centre of the circle. 

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Construct a triangle ABC, in which AB = 4.2 cm, BC = 6.3 cm and AC = 5 cm. Draw perpendicular bisector of BC which meets AC at point D. Prove that D is equidistant from B and C. 


Use ruler and compasses only for this question.

  1. Construct ΔABC, where AB = 3.5 cm, BC = 6 cm and ∠ABC = 60°.
  2. Construct the locus of points inside the triangle which are equidistant from BA and BC.
  3. Construct the locus of points inside the triangle which are equidistant from B and C.
  4. Mark the point P which is equidistant from AB, BC and also equidistant from B and C. Measure and record the length of PB.

Describe the locus of points at a distance 2 cm from a fixed line. 


Describe the locus of the centre of a wheel of a bicycle going straight along a level road.


The speed of sound is 332 metres per second. A gun is fired. Describe the locus of all the people on the earth’s surface, who hear the sound exactly one second later.


In the given figure, obtain all the points equidistant from lines m and n; and 2.5 cm from O. 


Draw a triangle ABC in which AB = 6 cm, BC = 4.5 cm and AC = 5 cm. Draw and label:

  1. the locus of the centres of all circles which touch AB and AC,
  2. the locus of the centres of all the circles of radius 2 cm which touch AB.
    Hence, construct the circle of radius 2 cm which touches AB and AC . 

In  Δ ABC, the perpendicular bisector of AB and AC meet at 0. Prove that O is equidistant from the three vertices. Also, prove that if M is the mid-point of BC then OM meets BC at right angles. 


ΔPBC and ΔQBC are two isosceles triangles on the same base. Show that the line PQ is bisector of BC and is perpendicular to BC.


Show that the locus of the centres of all circles passing through two given points A and B, is the perpendicular bisector of the line segment AB.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×