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प्रश्न
Given: ∠BAC, a line intersects the arms of ∠BAC in P and Q. How will you locate a point on line segment PQ, which is equidistant from AB and AC? Does such a point always exist?
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उत्तर
Since, locus of points equidistant from AB and AC is the bisector of ∠BAC. Draw the bisector of ∠BAC intersecting PQ at R.
Since,R is on the bisector, so it is equidistant from AB and AC.
Yes, such a point always exists as there will be definitely a point where angular bisector and line will intersect.
Hence, R is the required point.
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संबंधित प्रश्न
Describe the locus for questions 1 to 13 given below:
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Describe the locus of points at distances less than 3 cm from a given point.
Describe the locus of points at distances greater than 4 cm from a given point.
Describe the locus of points at distances greater than or equal to 35 mm from a given point.
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A straight line AB is 8 cm long. Draw and describe the locus of a point which is:
- always 4 cm from the line AB.
- equidistant from A and B.
Mark the two points X and Y, which are 4 cm from AB and equidistant from A and B. Describe the figure AXBY.
In Fig. ABCD is a quadrilateral in which AB = BC. E is the point of intersection of the right bisectors of AD and CD. Prove that BE bisects ∠ABC.
In Fig. AB = AC, BD and CE are the bisectors of ∠ABC and ∠ACB respectively such that BD and CE intersect each other at O. AO produced meets BC at F. Prove that AF is the right bisector of BC.
