हिंदी

Prove That: N ! ( N − R ) ! = N (N − 1) (N − 2) ... (N − (R − 1))

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प्रश्न

Prove that: 

\[\frac{n!}{(n - r)!}\] = n (n − 1) (n − 2) ... (n − (r − 1))
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उत्तर

\[ LHS = \frac{n!}{(n - r)!}\]
\[ = \frac{n\left( n - 1 \right)\left( n - 2 \right)\left( n - 3 \right)\left( n - 4 \right) . . . \left( n - r + 1 \right)\left[ \left( n - r \right)! \right]}{(n - r)!}\]
\[ = n\left( n - 1 \right)\left( n - 2 \right)\left( n - 3 \right)\left( n - 4 \right) . . . \left( n - r + 1 \right)\]
\[ = n\left( n - 1 \right)\left( n - 2 \right)\left( n - 3 \right)\left( n - 4 \right) . . . \left[ n - \left( r - 1 \right) \right] = RHS\]

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Factorial N (N!) Permutations and Combinations
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अध्याय 16: Permutations - Exercise 16.1 [पृष्ठ ५]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 16 Permutations
Exercise 16.1 | Q 11.1 | पृष्ठ ५

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