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If P (N − 1, 3) : P (N, 4) = 1 : 9, Find N. - Mathematics

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प्रश्न

If P (n − 1, 3) : P (n, 4) = 1 : 9, find n.

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उत्तर

P (n − 1, 3):P (n, 4) = 1:9

\[\Rightarrow \frac{\left( n - 1 \right)!}{(n - 1 - 3)!} \times \frac{(n - 4)!}{(n)!} = \frac{1}{9}\]
\[ \Rightarrow \frac{\left( n - 1 \right)!}{\left( n - 4 \right)!} \times \frac{\left( n - 4 \right)!}{n!} = \frac{1}{9}\]
\[ \Rightarrow \frac{\left( n - 1 \right)!}{n!} = \frac{1}{9}\]
\[ \Rightarrow \frac{\left( n - 1 \right)!}{n\left( n - 1 \right)!} = \frac{1}{9}\]
\[ \Rightarrow \frac{1}{n} = \frac{1}{9}\]
\[ \Rightarrow n = 9\]

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Factorial N (N!) Permutations and Combinations
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अध्याय 16: Permutations - Exercise 16.3 [पृष्ठ २८]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 16 Permutations
Exercise 16.3 | Q 9 | पृष्ठ २८

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