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प्रश्न
Out of C6H5CH2Cl and C6H5CHClC6H5, which is more easily hydrolysed by aqueous KOH.
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उत्तर
C6H5CHClC6H5 is hydrolysed faster.
- The hydrolysis of an alkyl halide is a nucleophilic substitution reaction. For aryl halides, this occurs through the SN1 method, resulting in a carbocation.
- C6H5CH2Cl or benzyl chloride gives
a carbocation, while C6H5CHClC6H5 generates 
. - Out of I and II, carbocation II is more stable. Two attached phenyl rings on the carbon carry the positive charge.
- This leads to increased delocalisation of the positive charge and greater carbocation stability. This leads to faster formation of (II) and easier hydrolysis of the resulting halide than benzyl chloride.
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संबंधित प्रश्न
Write the structure of an isomer of compound C4H9Br which is most reactive towards SN1 reaction
Write the major products(s) in the following:
Which compound in the following pair will react faster in SN2 reaction with OH−?
CH3Br or CH3I
Which compound in the following pair will react faster in SN2 reaction with OH−?
(CH3)3CCl or CH3Cl
How will you bring about the following conversion?
Toluene to benzyl alcohol
Write the structure of the major organic product in the following reaction:
\[\ce{CH3CH2Br + KCN ->[aq{.} ethanol]}\]
Identify 'A' in the following reaction -
(a) 2- Bromo-2 methylbutane
(b) 1 -Bromo-2,2-dimethylpropane
(c) 1 - Bromo - 3 -methylbutane
(d) 1 - Bromo- 2 -methylpropane
Which of the following is optically inactive?
The process of separation of a racemic modification into d and l-enantiomers is called ____________.
2-Bromopentane is heated with potassium ethoxide in ethanol. The major product obtained is ____________.
An organic molecule necessarily shows optical activity if it ____________.
SN1 reaction of alkyl halides lead to ___________.
Identify the end product (C) in the following sequence:
\[\ce{C2H5OH ->[SOCl2][Pyridine] A ->[KCN {(alc.)}] B ->[2H2O/H^+] C}\]
Which of the following alkyl halides will undergo SN1 reaction most readily?
Compound ‘A’ with molecular formula \[\ce{C4H9Br}\] is treated with aq. \[\ce{KOH}\] solution. The rate of this reaction depends upon the concentration of the compound ‘A’ only. When another optically active isomer ‘B’ of this compound was treated with aq. \[\ce{KOH}\] solution, the rate of reaction was found to be dependent on concentration of compound and \[\ce{KOH}\] both.
(i) Write down the structural formula of both compounds ‘A’ and ‘B’.
(ii) Out of these two compounds, which one will be converted to the product with inverted configuration.
Which one is the correct order of nucleophilic strength (pKa) of following nucleophiles?
Acetic anhydride from acetic acid
Which of the following is halogen exchange reaction?
The correct order of increasing reactivity of
C-X bond towards nucleophile in the following compounds is:
