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Let C be the set of complex numbers. Prove that the mapping f: C → R given by f(z) = |z|, ∀ z ∈ C, is neither one-one nor onto. - Mathematics

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प्रश्न

Let C be the set of complex numbers. Prove that the mapping f: C → R given by f(z) = |z|, ∀ z ∈ C, is neither one-one nor onto.

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उत्तर

Given, f: C → R such that f(z) = |z|, ∀ z ∈ C

Now, let take z = 6 + 8i

Then,

f(6 + 8i) = |6 + 8i|

= `sqrt(6^2 + 8^2)` 

= `sqrt(100)`

= 10

And, for z = 6 – 8i

f(6 – 8i) = |6 – 8i|

= `sqrt(6^2 - 8^2)` 

= `sqrt(100)`

= 10

Hence, f(z) is many-one.

Also, |z| ≥ 0, ∀ z ∈ C

But the co-domain given is ‘R’

Therefore, f(z) is not onto.

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अध्याय 1: Relations And Functions - Exercise [पृष्ठ ११]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 1 Relations And Functions
Exercise | Q 10 | पृष्ठ ११

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