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If F : R → R Be Defined by F(X) = X3 −3, Then Prove that F−1 Exists and Find a Formula for F−1. Hence, Find F−1 (24) and F−1 (5).

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प्रश्न

If f : R → R be defined by f(x) = x3 −3, then prove that f−1 exists and find a formula for f−1. Hence, find f−1(24) and f−1 (5).

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उत्तर

Injectivity of f :
Let x and y be two elements in domain (R),

such that,  x3 − 3 = y3 − 3            

⇒ x3 = y3        

⇒ x = y

So, f is one-one.

Surjectivity of f :
Let y be in the co-domain (R) such that f(x) = y

⇒ x3 - 3 = y

⇒  x3 = y + 3 

⇒ `x = 3sqrt(y+3) in R`

⇒ f is onto.
So, f is a bijection and, hence, it is invertible.

Finding f  -1:

Let f−1(x) = y               ...(1)

⇒ x= f( y)

⇒ x = y3−3

⇒ x + 3 = y3

⇒  `y = 3sqrt(x+3)  = f^-1 (x)`         [from (1)]

`So, f^-1 (x) = 3sqrt(x+3)`

Now`, f^1 (24) = 3sqrt(24+3) = 3sqrt27 = 3sqrt3^3 =3`

and `f^-1 (5) = 3sqrt(5+3) = 3 sqrt8 = 3sqrt2^3 =2`

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अध्याय 2: Functions - Exercise 2.4 [पृष्ठ ६९]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 2 Functions
Exercise 2.4 | Q 10 | पृष्ठ ६९

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