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Let A = [–1, 1]. Then, discuss whether the following functions defined on A are one-one, onto or bijective: h(x) = x|x|

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प्रश्न

Let A = [–1, 1]. Then, discuss whether the following functions defined on A are one-one, onto or bijective:

h(x) = x|x|

योग
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उत्तर

Given, A = [–1, 1]

Let h(x1) = h(x2)

x1|x1| = x2|x2|

If x1, x2 > 0

x12 = x22

x12 – x22 = 0

(x1 – x2)(x1 + x2) = 0

x1 = x2 (as x1 + x2 ≠ 0)

Similarly for x1, x2 < 0, we have x1 = x2

It’s clearly seen that for x1 and x2 of opposite sign, x1 ≠ x2.

Hence, f(x) is one-one.

For x ∈ [0, 1], f(x) = x2 ∈ [0, 1]

For x < 0, f(x) = – x2 ∈ [–1, 0)

Hence, the range is [–1, 1].

So, h(x) is onto.

Therefore, h(x) is bijective.

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अध्याय 1: Relations And Functions - Exercise [पृष्ठ १२]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
अध्याय 1 Relations And Functions
Exercise | Q 21. (iii) | पृष्ठ १२

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