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In the given figure, BC ⊥ AB, AD ⊥ AB, BC = 4, AD = 8, then find AABCAADBA(∆ABC)A(∆ADB)

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प्रश्न

In the given figure, BC ⊥ AB, AD ⊥ AB, BC = 4, AD = 8, then find `("A"(∆"ABC"))/("A"(∆"ADB"))`

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उत्तर

In ∆ABC and ∆ADB,
BC ⊥ AB, AD ⊥ AB, BC = 4, AD = 8   ...(Given)

∆ABC and ∆ADB have same base AB. ...(Given)

∴ Areas of triangles with equal bases are proportional to their corresponding heights.

`("A"(∆"ABC"))/("A"(∆"ADB")) = "BC"/"AD"`

∴ `("A"(∆"ABC"))/("A"(∆"ADB")) = 4/8`

∴ `("A"(∆"ABC"))/("A"(∆"ADB")) = 1/2`.

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अध्याय 1: Similarity - Practice Set 1.1 [पृष्ठ ६]

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बालभारती Geometry Mathematics 2 [English] Standard 10 Maharashtra State Board
अध्याय 1 Similarity
Practice Set 1.1 | Q 2 | पृष्ठ ६

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In adjoining figure, PQ ⊥ BC, AD ⊥ BC then find following ratios.

  1. `("A"(∆"PQB"))/("A"(∆"PBC"))`
  2. `("A"(∆"PBC"))/("A"(∆"ABC"))`
  3. `("A"(∆"ABC"))/("A"(∆"ADC"))`
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In fig., TP = 10 cm, PS = 6 cm. `(A(ΔRTP))/(A(ΔRPS))` = ?


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Therefore, 

`(A(ΔPQB))/(A(ΔPBC)) = (1/2 xx square xx square)/(1/2 xx square xx square)`

= `square/square`


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