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The Ratio of the Areas of Two Triangles with the Common Base is 4 : 3. Height of the Larger Triangle is 2 Cm, Then Find the Corresponding Height of the Smaller Triangle.

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प्रश्न

The ratio of the areas of two triangles with the common base is 4 : 3. Height of the larger triangle is 2 cm, then find the corresponding height of the smaller triangle.

योग
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उत्तर

Let the height of the larger triangle be h1 and that of the smaller triangle be h2.

The ratio of the areas of two triangles with a common base is equal to the ratio of their corresponding heights.

`"Area(larger Triangle)"/"Area(smaller Triangle)"="h"_1/"h"_2`

`4/3=2/"h"_2`

`4xx "h"_2=3xx2`

`therefore"h"_2=(3xx2)/4=6/4`

`therefore"h"_2=1.5" cm"`

The corresponding height of the smaller triangle is 1.5 cm.

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2014-2015 (March) Set A

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In the figure, PQ ⊥ BC, AD ⊥ BC. To find the ratio of A(ΔPQB) and A(ΔPBC), complete the following activity.


Given: PQ ⊥ BC, AD ⊥ BC

Now, A(ΔPQB)  = `1/2 xx square xx square`

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Therefore, 

`(A(ΔPQB))/(A(ΔPBC)) = (1/2 xx square xx square)/(1/2 xx square xx square)`

= `square/square`


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