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प्रश्न
In fig., TP = 10 cm, PS = 6 cm. `(A(ΔRTP))/(A(ΔRPS))` = ?
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उत्तर
Draw RE ⊥ TS, T-E-S
ΔRTP and ΔRPS have same height RE.
`(A(ΔRTP))/(A(ΔRPS)) = (TP)/(PS)` ...[Triangles having equal height]
`(A(ΔRTP))/(A(ΔRPS)) = 10/6` ...[Given]
∴ `(A(ΔRTP))/(A(ΔRPS)) = 5/3`
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In the figure, PQ ⊥ BC, AD ⊥ BC. To find the ratio of A(ΔPQB) and A(ΔPBC), complete the following activity.
Given: PQ ⊥ BC, AD ⊥ BC
Now, A(ΔPQB) = `1/2 xx square xx square`
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Therefore,
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= `square/square`
