हिंदी
तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान कक्षा १२

Identify the type of conic and find centre, foci, vertices, and directrices of the following: (x+3)2225+(y-4)264 = 1 - Mathematics

Advertisements
Advertisements

प्रश्न

Identify the type of conic and find centre, foci, vertices, and directrices of the following:

`(x + 3)^2/225 + (y - 4)^2/64` = 1

योग
Advertisements

उत्तर

It is an hyperbola.

The transverse axis is parallell to x axis.

a2= 225, b2 = 64

a = 15, b = 8

c2 = a2 – b2

= 225 + 64

c2 = 289

c = 17

ae = 17

5e = 17

e = `17/15`

Centre (h, k) = (– 3, 4)

Vertices (h ± a, k) = (– 3 ± 15, 4)

= (– 3 + 15, 4) and (– 3 – 15, 4)

= (12, 4) and (– 18, 4)

Foci (h ± c, k) = (– 3 ± 17, 4)

= (– 3 + 17, 4) and (– 3 – 17, 4)

= (14, 4) and (– 20, 4)

Directrix x = `+-  "a"/"e" + "h"`

= `+-  15/(17/5) - 3`

= `+-  225/17 - 3`

x = `225/17 - 3` and x = `- 225/17 - 3`

= `174/17` and = `(- 276)/17`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Two Dimensional Analytical Geometry-II - Exercise 5.2 [पृष्ठ १९७]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 5 Two Dimensional Analytical Geometry-II
Exercise 5.2 | Q 8. (iii) | पृष्ठ १९७

संबंधित प्रश्न

Find the equation of the parabola whose focus is the point F(-1, -2) and the directrix is the line 4x – 3y + 2 = 0.


The parabola y2 = kx passes through the point (4, -2). Find its latus rectum and focus.


Find the vertex, focus, axis, directrix, and the length of the latus rectum of the parabola y2 – 8y – 8x + 24 = 0.


Find the co-ordinates of the focus, vertex, equation of the directrix, axis and the length of latus rectum of the parabola

y2 = 20x


Find the co-ordinates of the focus, vertex, equation of the directrix, axis and the length of latus rectum of the parabola

x2 = 8y


Find the co-ordinates of the focus, vertex, equation of the directrix, axis and the length of latus rectum of the parabola

x2 = - 16y


The profit ₹ y accumulated in thousand in x months is given by y = -x2 + 10x – 15. Find the best time to end the project.


Find the equation of the parabola which is symmetrical about x-axis and passing through (–2, –3).


Find the axis, vertex, focus, equation of directrix and the length of latus rectum of the parabola (y - 2)2 = 4(x - 1)


The focus of the parabola x2 = 16y is:


The eccentricity of the parabola is:


The distance between directrix and focus of a parabola y2 = 4ax is:


Find the equation of the ellipse in the cases given below:

Foci `(+- 3, 0), "e"+ 1/2`


Find the equation of the hyperbola in the cases given below:

Foci (± 2, 0), Eccentricity = `3/2`


Find the equation of the hyperbola in the cases given below:

Passing through (5, – 2) and length of the transverse axis along x-axis and of length 8 units


Find the vertex, focus, equation of directrix and length of the latus rectum of the following:

y2 = – 8x


Show that the absolute value of difference of the focal distances of any point P on the hyperbola is the length of its transverse axis


Identify the type of conic and find centre, foci, vertices, and directrices of the following:

9x2 – y2 – 36x – 6y + 18 = 0


A chord passing through any point on the conic and perpendicular to the axis is called:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×