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Identify the type of conic and find centre, foci, vertices, and directrices of the following: (x+3)2225+(y-4)264 = 1 - Mathematics

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प्रश्न

Identify the type of conic and find centre, foci, vertices, and directrices of the following:

`(x + 3)^2/225 + (y - 4)^2/64` = 1

योग
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उत्तर

It is an hyperbola.

The transverse axis is parallell to x axis.

a2= 225, b2 = 64

a = 15, b = 8

c2 = a2 – b2

= 225 + 64

c2 = 289

c = 17

ae = 17

5e = 17

e = `17/15`

Centre (h, k) = (– 3, 4)

Vertices (h ± a, k) = (– 3 ± 15, 4)

= (– 3 + 15, 4) and (– 3 – 15, 4)

= (12, 4) and (– 18, 4)

Foci (h ± c, k) = (– 3 ± 17, 4)

= (– 3 + 17, 4) and (– 3 – 17, 4)

= (14, 4) and (– 20, 4)

Directrix x = `+-  "a"/"e" + "h"`

= `+-  15/(17/5) - 3`

= `+-  225/17 - 3`

x = `225/17 - 3` and x = `- 225/17 - 3`

= `174/17` and = `(- 276)/17`

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Conics
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Two Dimensional Analytical Geometry-II - Exercise 5.2 [पृष्ठ १९७]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 5 Two Dimensional Analytical Geometry-II
Exercise 5.2 | Q 8. (iii) | पृष्ठ १९७

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