Find the vertex, focus, equation of directrix and length of the latus rectum of the following: y2 = - 8x

Find the vertex, focus, equation of directrix and length of the latus rectum of the following:

y² = – 8x

योग

4a = 8

a = 2

(a) Vertex V(0, 0) = (0, 0)

(b) Focus S(– a, 0) = (– 2, 0)

(c) Equation of the directrix x = a = 2

x – 2 = 0

(d) Length of the latus rectum 4a = 8

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अध्याय 5: Two Dimensional Analytical Geometry-II - Exercise 5.2 [पृष्ठ १९७]

अध्याय 5 Two Dimensional Analytical Geometry-II
Exercise 5.2 | Q 4. (iii) | पृष्ठ १९७

Find the co-ordinates of the focus, vertex, equation of the directrix, axis and the length of latus rectum of the parabola

x² = - 16y

Find the equation of the parabola which is symmetrical about x-axis and passing through (–2, –3).

The focus of the parabola x² = 16y is:

The eccentricity of the parabola is:

Find the equation of the parabola in the cases given below:

Vertex (1, – 2) and Focus (4, – 2)

Find the equation of the parabola in the cases given below:

End points of latus rectum (4, – 8) and (4, 8)

Find the equation of the ellipse in the cases given below:

Foci (0, ±4) and end points of major axis are (0, ±5)

Find the equation of the ellipse in the cases given below:

Length of latus rectum 4, distance between foci `4sqrt(2)`, centre (0, 0) and major axis as y-axis

Find the vertex, focus, equation of directrix and length of the latus rectum of the following:

x² = 24y