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Find the equation of the ellipse in the cases given below: Foci e(±3,0),e+12 - Mathematics

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प्रश्न

Find the equation of the ellipse in the cases given below:

Foci `(+- 3, 0), "e"+ 1/2`

योग
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उत्तर

Foci (± c, 0) = (± 3, 0)

e = `1/2`

c = ae = 3

`"a"(1/2)` = 3

a = 6 ⇒ a² = 36

b2 = a2 – c2

b2 = 36 – 9 = 27

b2 = 27

Equation of the ellipse be `x^2/"a"^2 + y^2/"b"^2` = 1

`x^2/36 + y^2/27` = 1

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Two Dimensional Analytical Geometry-II - Exercise 5.2 [पृष्ठ १९६]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 5 Two Dimensional Analytical Geometry-II
Exercise 5.2 | Q 2. (i) | पृष्ठ १९६

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