मराठी
तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान इयत्ता १२

Identify the type of conic and find centre, foci, vertices, and directrices of the following: (x+3)2225+(y-4)264 = 1 - Mathematics

Advertisements
Advertisements

प्रश्न

Identify the type of conic and find centre, foci, vertices, and directrices of the following:

`(x + 3)^2/225 + (y - 4)^2/64` = 1

बेरीज
Advertisements

उत्तर

It is an hyperbola.

The transverse axis is parallell to x axis.

a2= 225, b2 = 64

a = 15, b = 8

c2 = a2 – b2

= 225 + 64

c2 = 289

c = 17

ae = 17

5e = 17

e = `17/15`

Centre (h, k) = (– 3, 4)

Vertices (h ± a, k) = (– 3 ± 15, 4)

= (– 3 + 15, 4) and (– 3 – 15, 4)

= (12, 4) and (– 18, 4)

Foci (h ± c, k) = (– 3 ± 17, 4)

= (– 3 + 17, 4) and (– 3 – 17, 4)

= (14, 4) and (– 20, 4)

Directrix x = `+-  "a"/"e" + "h"`

= `+-  15/(17/5) - 3`

= `+-  225/17 - 3`

x = `225/17 - 3` and x = `- 225/17 - 3`

= `174/17` and = `(- 276)/17`

shaalaa.com
Conics
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 5: Two Dimensional Analytical Geometry-II - Exercise 5.2 [पृष्ठ १९७]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 5 Two Dimensional Analytical Geometry-II
Exercise 5.2 | Q 8. (iii) | पृष्ठ १९७

संबंधित प्रश्‍न

Find the equation of the parabola whose focus is the point F(-1, -2) and the directrix is the line 4x – 3y + 2 = 0.


Find the co-ordinates of the focus, vertex, equation of the directrix, axis and the length of latus rectum of the parabola

y2 = 20x


Find the equation of the parabola which is symmetrical about x-axis and passing through (–2, –3).


The eccentricity of the parabola is:


The double ordinate passing through the focus is:


The equation of directrix of the parabola y2 = -x is:


Find the equation of the parabola in the cases given below:

Focus (4, 0) and directrix x = – 4


Find the equation of the parabola in the cases given below:

Passes through (2, – 3) and symmetric about y-axis


Find the equation of the ellipse in the cases given below:

Foci (0, ±4) and end points of major axis are (0, ±5)


Find the equation of the ellipse in the cases given below:

Length of latus rectum 8, eccentricity = `3/5` centre (0, 0) and major axis on x-axis


Find the equation of the ellipse in the cases given below:

Length of latus rectum 4, distance between foci `4sqrt(2)`, centre (0, 0) and major axis as y-axis


Find the equation of the hyperbola in the cases given below:

Centre (2, 1), one of the foci (8, 1) and corresponding directrix x = 4


Find the vertex, focus, equation of directrix and length of the latus rectum of the following:

x2 = 24y


Find the vertex, focus, equation of directrix and length of the latus rectum of the following:

y2 = – 8x


Identify the type of conic and find centre, foci, vertices, and directrices of the following:

`y^2/16 - x^2/9` = 1


Choose the correct alternative:

The eccentricity of the hyperbola whose latus rectum is 8 and conjugate axis is equal to half the distance between the foci is


Choose the correct alternative:

If P(x, y) be any point on 16x2 + 25y2 = 400 with foci F(3, 0) then PF1 + PF2 is


Choose the correct alternative:

If x + y = k is a normal to the parabola y2 = 12x, then the value of k is 14


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×