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Find the equation of the parabola in the cases given below: Passes through (2, – 3) and symmetric about y-axis

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प्रश्न

Find the equation of the parabola in the cases given below:

Passes through (2, – 3) and symmetric about y-axis

बेरीज
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उत्तर


x2 = 4ay

It passes through (2, – 3)

⇒ 22 = 4a(– 3)

4 = – 12a

⇒ a = `- 1/3`

⇒ 4a = `- 4/3`

∴ Equation of parabola is x2 = `- 4/3`y

3x2= – 4y

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पाठ 5: Two Dimensional Analytical Geometry-II - Exercise 5.2 [पृष्ठ १९६]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 5 Two Dimensional Analytical Geometry-II
Exercise 5.2 | Q 1. (ii) | पृष्ठ १९६

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