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Find the equation of the parabola in the cases given below: Focus (4, 0) and directrix x = – 4

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प्रश्न

Find the equation of the parabola in the cases given below:

Focus (4, 0) and directrix x = – 4

बेरीज
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उत्तर

Focus (4, 0) and directrix x = – 4

Parabola is open rightwards vertex (0, 0)

a = 4

Distance AS = 4 unit

F2 = 4(4)x

Equation of parabola

y2 = 16x.

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पाठ 5: Two Dimensional Analytical Geometry-II - Exercise 5.2 [पृष्ठ १९६]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 5 Two Dimensional Analytical Geometry-II
Exercise 5.2 | Q 1. (i) | पृष्ठ १९६

संबंधित प्रश्‍न

Find the equation of the parabola whose focus is the point F(-1, -2) and the directrix is the line 4x – 3y + 2 = 0.


The parabola y2 = kx passes through the point (4, -2). Find its latus rectum and focus.


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The focus of the parabola x2 = 16y is:


The eccentricity of the parabola is:


The double ordinate passing through the focus is:


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