Advertisements
Advertisements
प्रश्न
Find the equation of the parabola which is symmetrical about x-axis and passing through (–2, –3).
Advertisements
उत्तर

Equation of the parabola symmetrical about X-axis is either y2 = 4ax or y2 = - 4ax.
Since the parabola passes through (-2, -3) it will be of the form y2 = - 4ax ...(1)
Substituting (-2, -3) in (1) we get,
y2 = - 4ax
(-3)2 = - 4a(-2)
⇒ 9 = 8a
⇒ a = `9/8`
Substituting a = `9/8` in (1) we get,
y2 = - 4ax
y2 = - 4`(9/8)`x
⇒ y2 = `(-9)/2`x
which is required equation of the parabola.
APPEARS IN
संबंधित प्रश्न
Find the co-ordinates of the focus, vertex, equation of the directrix, axis and the length of latus rectum of the parabola
y2 = 20x
The focus of the parabola x2 = 16y is:
The distance between directrix and focus of a parabola y2 = 4ax is:
Find the equation of the ellipse in the cases given below:
Foci `(+- 3, 0), "e"+ 1/2`
Find the equation of the ellipse in the cases given below:
Length of latus rectum 8, eccentricity = `3/5` centre (0, 0) and major axis on x-axis
Find the equation of the hyperbola in the cases given below:
Passing through (5, – 2) and length of the transverse axis along x-axis and of length 8 units
Find the vertex, focus, equation of directrix and length of the latus rectum of the following:
y2 – 4y – 8x + 12 = 0
Identify the type of conic and find centre, foci, vertices, and directrices of the following:
`x^2/3 + y^2/10` = 1
Identify the type of conic and find centre, foci, vertices, and directrices of the following:
`(x + 3)^2/225 + (y - 4)^2/64` = 1
Choose the correct alternative:
If x + y = k is a normal to the parabola y2 = 12x, then the value of k is 14
