Advertisements
Advertisements
प्रश्न
Find the co-ordinates of the focus, vertex, equation of the directrix, axis and the length of latus rectum of the parabola
y2 = 20x
Advertisements
उत्तर
y2 = 20x
y2 = 4(5)x
∴ a = 5
| Vertex | (0, 0) | (0, 0) |
| Focus | (a, 0) | (5, 0) |
| Axis | x-axis | y = 0 |
| Directrix | x + a = 0 | x + 5 = 0 |
| Length of Latus rectum | 4a | 20 |
APPEARS IN
संबंधित प्रश्न
The eccentricity of the parabola is:
The double ordinate passing through the focus is:
Find the equation of the parabola in the cases given below:
Passes through (2, – 3) and symmetric about y-axis
Find the equation of the hyperbola in the cases given below:
Passing through (5, – 2) and length of the transverse axis along x-axis and of length 8 units
Find the vertex, focus, equation of directrix and length of the latus rectum of the following:
x2 = 24y
Identify the type of conic and find centre, foci, vertices, and directrices of the following:
`y^2/16 - x^2/9` = 1
Identify the type of conic and find centre, foci, vertices, and directrices of the following:
`(x + 3)^2/225 + (y - 4)^2/64` = 1
Identify the type of conic and find centre, foci, vertices, and directrices of the following:
`(y - 2)^3/25 + (x + 1)^2/16` = 1
Choose the correct alternative:
If x + y = k is a normal to the parabola y2 = 12x, then the value of k is 14
If the eccentricity e > 1, the conic section is:
