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Find the equation of the hyperbola in the cases given below: Foci (± 2, 0), Eccentricity = 32

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प्रश्न

Find the equation of the hyperbola in the cases given below:

Foci (± 2, 0), Eccentricity = `3/2`

योग
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उत्तर

e = `3/2`

Foci (±c ,0) = (±2, 0)

c = 2

ae = 2

`a(3/2)` = 2

a = `4/3`, a2 = `16/9`

b2 = c2 – a2

= `4 - 16/9`

= `20/9`

Equation of hyperbola

`x^2/"a"^2 - y^2/"b"^2` = 1

`x^2/(16/9) - y^2/(20/9)` = 1

`(9x^2)/16 - (9y^2)/20` = 1

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अध्याय 5: Two Dimensional Analytical Geometry-II - Exercise 5.2 [पृष्ठ १९६]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 5 Two Dimensional Analytical Geometry-II
Exercise 5.2 | Q 3. (i) | पृष्ठ १९६

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