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Given the p.d.f. of a continuous r.v. X , f (x) = x23 ,for –1 < x < 2 and = 0 otherwise Determine c.d.f. of X hence find P( x < 1) - Mathematics and Statistics

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प्रश्न

Given the p.d.f. of a continuous r.v. X , f (x) = `x^2/3` ,for –1 < x < 2 and = 0 otherwise

Determine c.d.f. of X hence find

P( x < 1) 

योग
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उत्तर

Let F(x) be the c.d.f. of X

Then F(x) = ` int_(-∞)^x f (x) dx`

=` int_(-∞)^-1 f (x) dx + int_(-1)^x f (x) dx`

= 0 + `int_(-1)^x  x^2/3 dx = 1/3int_(-1)^x  x^2 dx`

= `1/3[x^3/3]_-1^x`

= `1/3[x^3/3-(-1/3)]`

∴ f(x) = `(x^3+1)/9`

P( x < 1)  = `F (1) - F (-1) - [(1^3 + 1)/9]- [((-1)^3 + 1)/9]- (2-0)/9-2/9`

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Types of Random Variables
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Probability Distributions - Exercise 7.2 [पृष्ठ २३९]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 7 Probability Distributions
Exercise 7.2 | Q 9.1 | पृष्ठ २३९

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