Advertisements
Advertisements
प्रश्न
Find the probability mass function and cumulative distribution function of a number of girl children in families with 4 children, assuming equal probabilities for boys and girls
Advertisements
उत्तर
Let X be the random variable denotes the number of girl child among 4 children
X = {0, 1, 2, 3, 4}
| Values of the random variable | 0 | 1 | 2 | 3 | 4 | Total |
| Number of elements in inverse image | 1 | 4 | 6 | 4 | 1 | 16 |
(i) Probability mass function
| x | 0 | 1 | 2 | 3 | 4 | Total |
| f(x) | `1/16` | `4/16` | `6/16` | `4/16` | `1/16` | 1 |

(ii) Cumulative distribution
F(x) = P(X ≤ x)
= `sum_(x_"i" ≤ x) "P"("X" = x_"i")`
P(X < 0) = 0 for `- oo < x < 0`
F(0) = P(X ≤ 0)
= `P(X = 0)
= `1/16`
F(1) = P(X ≤ 1) = P(X = 0) + P(X = 1)`
= `1/16 + 4/16`
= `5/16`
F(2) = P(X ≤ 2)
= P(X = 0) + P(X = 1) + P(X = 2)
= `1/16 + 4/16 + 6/16`
= `11/16`
F(3) = P(X ≤ 3)
= P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)
= `1/16 + 4/16 + 6/16 + 4/16`
= `15/16`
F(4) = P(X ≤ 4)
= P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)
= `15/16 + 1/16`
= 1
F(x) = `{{:(0",", "For" x < 0),(1/16",", "For" x ≤ 0),(5/16",", "For" x ≤ 1), (11/16",", "For" x ≤ 2),(15/16",", "For" x ≤ 3),(1",", "For" x ≤ 4):}`

APPEARS IN
संबंधित प्रश्न
Given the p.d.f. of a continuous r.v. X , f (x) = `x^2/3` ,for –1 < x < 2 and = 0 otherwise
Determine c.d.f. of X hence find
P( x < 1)
Given the p.d.f. of a continuous r.v. X ,
f (x) = `x^2 /3` , for –1 < x < 2 and = 0 otherwise
Determine c.d.f. of X hence find P( x < –2)
Choose the correct option from the given alternative:
If the a d.r.v. X has the following probability distribution:
| X | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| P(X=x) | k | 2k | 2k | 3k | k2 | 2k2 | 7k2+k |
k =
Solve the following problem :
Identify the random variable as discrete or continuous in each of the following. Identify its range if it is discrete.
A highway safety group is interested in the speed (km/hrs) of a car at a check point.
c.d.f. of a discrete random variable X is
Suppose a discrete random variable can only take the values 0, 1, and 2. The probability mass function is defined by
`f(x) = {{:((x^2 + 1)/k"," "for" x = 0"," 1"," 2),(0"," "otherwise"):}`
Find P(X ≥ 1)
The cumulative distribution function of a discrete random variable is given by
F(x) = `{{:(0, - oo < x < - 1),(0.15, - 1 ≤ x < 0),(0.35, 0 ≤ x < 1),(0.60, 1 ≤ x < 2),(0.85, 2 ≤ x < 3),(1, 3 ≤ x < oo):}`
Find P(X ≥ 2)
A random variable X has the following probability mass function.
| x | 1 | 2 | 3 | 4 | 5 |
| F(x) | k2 | 2k2 | 3k2 | 2k | 3k |
Find P(2 ≤ X < 5)
The cumulative distribution function of a discrete random variable is given by
F(x) = `{{:(0, "for" - oo < x < 0),(1/2, "for" 0 ≤ x < 1),(3/5, "for" 1 ≤ x < 2),(4/5, "for" 2 ≤ x < 4),(9/5, "for" 3 ≤ x < 4),(1, "for" ≤ x < oo):}`
Find P(X < 3)
Choose the correct alternative:
The probability mass function of a random variable is defined as:
| x | – 2 | – 1 | 0 | 1 | 2 |
| f(x) | k | 2k | 3k | 4k | 5k |
Then E(X ) is equal to:
A bag contains 6 white and 4 black balls. Two balls are drawn at random. The probability that they are of the same colour is ______.
If A = {x ∈ R : x2 - 5 |x| + 6 = 0}, then n(A) = _____.
X is a continuous random variable with a probability density function
f(x) = `{{:(x^2/4 + k; 0 ≤ x ≤ 2),(0; "otherwise"):}`
The value of k is equal to ______
The probability distribution of a random variable X is given below.
| X = k | 0 | 1 | 2 | 3 | 4 |
| P(X = k) | 0.1 | 0.4 | 0.3 | 0.2 | 0 |
The variance of X is ______
A card is chosen from a well-shuffled pack of cards. The probability of getting an ace of spade or a jack of diamond is ______.
Two coins are tossed. Then the probability distribution of number of tails is.
The c.d.f. of a discrete r.v. x is
| x | 0 | 1 | 2 | 3 | 4 | 5 |
| F(x) | 0.16 | 0.41 | 0.56 | 0.70 | 0.91 | 1.00 |
Then P(1 < x ≤ 4) = ______
The p.d.f. of a continuous random variable X is
f(x) = 0.1 x, 0 < x < 5
= 0, otherwise
Then the value of P(X > 3) is ______
If f(x) = `k/2^x` is a probability distribution of a random variable X that can take on the values x = 0, 1, 2, 3, 4. Then, k is equal to ______.
