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Given P01(M-E) = 120, ∑p1q1 = 300, ∑p0q0 = 120, ∑p0q1 = 320, Find P01(L) - Mathematics and Statistics

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प्रश्न

Given P01(M-E) = 120, `sum"p"_1"q"_1` = 300, `sum"p"_0"q"_0` = 120, `sum"p"_0"q"_1` = 320, Find P01(L)

योग
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उत्तर

Given, P01(M-E) = 120, `sum"p"_1"q"_1` = 300, `sum"p"_0"q"_0` = 120, `sum"p"_0"q"_1` = 320

P01(M-E) = `(sum"p"_1"q"_0 + sum"p"_1"q"_1)/(sum"p"_0"q"_0 + sum"p"_0"q"_1) xx 100`

∴ 120 = `(sum"p"_1"q"_0 + 300)/(120 + 130) xx 100`

∴ 120 = `(sum"p"_1"q"_0 + 300)/440 xx 100`

∴ `sum"p"_1"q"_0 + 300 = (120 xx 440)/100`

∴ `sum"p"_1"q"_0 + 300` = 528

∴ `sum"p"_1"q"_0` = 528 – 300

∴ `sum"p"_1"q"_0` = 228

Laspeyre’s Price Index Number:

P01(L) = `(sum"p"_1"q"_0)/(sum"p"_0"q"_0) xx 100`

= `228/120 xx 100`

= 190

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Construction of Index Numbers - Weighted Aggregate Method
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अध्याय 2.5: Index Numbers - Q.4

संबंधित प्रश्न

Calculate Laspeyre’s, Paasche’s, Dorbish-Bowley’s, and MarshallEdgeworth’s Price index numbers.

Commodity Base Year Current Year
Price Quantity Price Quantity
A 8 20 11 15
B 7 10 12 10
C 3 30 5 25
D 2 50 4 35

Given that ∑p0q0 = 220, ∑p0q1 = 380, ∑p1q1 = 350 and Marshall-Edgeworth’s Price Index Number is 150, find Laspeyre’s Price Index Number.


Find x in the following table if Laspeyre’s and Paasche’s Price Index Numbers are equal.

Commodity Base Year Current year
Price Quantity Price Quantity
A 2 10 2 5
B 2 5 x 2

If Dorbish-Bowley's and Fisher's Price Index Numbers are 5 and 4, respectively, then find Laspeyre's and Paasche's Price Index Numbers.


Choose the correct alternative :

The price Index Number by Weighted Aggregate Method is given by ______.


Paasche’s Price Index Number is given by ______.


Choose the correct alternative :

Fisher’s Price Number is given by


Choose the correct alternative :

Marshall-Edgeworth’s Price Index Number is given by


Laspeyre’s Price Index Number is given by _______.


Fill in the blank :

Dorbish-Bowley’s Price Index Number is given by _______.


`(sump_1q_0)/(sump_0q_0) xx 100` is Paasche’s Price Index Number.


State whether the following is True or False :

`sum("p"_1"q"_1)/("p"_0"q"_1)` is Laspeyre’s Price Index Number.


State whether the following is True or False :

`(sum"p"_1"q"_0)/(sum"p"_0"q"_0) xx (sum"p"_1"q"_0)/(sum"p"_0"q"_0) xx 100` is Dorbish-Bowley’s Price Index Number.


Solve the following problem :

Calculate Laspeyre’s and Paasche’s Price Index Number for the following data.

Commodity Base Year Current Year
  Price
P0
Quantity
q0
Price
p1
Quantity
q1
I 8 30 12 25
II 10 42 20 16

Solve the following problem:

If find x is Walsh’s Price Index Number is 150 for the following data

Commodity Base Year Current Year
  Price
p0
Quantity
q0
Price
p1
Quantity
q1
A 5 3 10 3
B x 4 16 9
C 15 5 23 5
D 10 2 26 8

If Laspeyre’s and Dorbish’s Price Index Numbers are 150.2 and 152.8 respectively, find Paasche’s Price Index Number.


Choose the correct alternative:

The formula P01 = `(sum"p"_1"q"_0)/(sum"p"_0"q"_0) xx 100` is for


Choose the correct alternative:

Dorbish–Bowley’s Price Index Number is


The average of Laspeyre’s and Paasche’s Price Index Numbers is called ______ Price Index Number


State whether the following statement is True or False:

Walsh’s Price Index Number is given by `(sum"p"_1sqrt("q"_0"q"_1))/(sum"p"_0sqrt("q"_0"q"_1)) xx 100`


State whether the following statement is True or False:

`(sum"p"_1"q"_1)/(sum"p"_0"q"_1) xx 100` is Paasche’s Price Index Number


State whether the following statement is True or False:

`(sum"p"_0sqrt("q"_0 + "q"_1))/(sum"p"_1sqrt("q"_0 + "q"_1)) xx 100` is Marshall-Edgeworth Price Index Number


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Commodity Base Year Current Year
Price Quantity Price Quantity
A 1 10 2 5
B 1 12

State whether the following statement is true or false:

Dorbish-Bowley's Price Index Number is the square root of the product of Laspeyre's and Paasche's Index Numbers.


If P01 (L) = 121, P01 (P) = 100, then P01 (F) = ______.


In the following table, Laspeyre's and Paasche's Price Index Numbers are equal. Complete the following activity to find x :

Commodity Base Year Current year
Price Quantity Price Quantity
A 2 10 2 5
B 2 5 x 2

Solution: P01(L) = P01(P)

`(sum "p"_1"q"_0)/(sum "p"_0"q"_0) xx 100 = square/(sum "p"_0"q"_1) xx 100`

`(20 + 5x)/square xx 100 = square/14 xx 100`

∴ x = `square`


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