Advertisements
Advertisements
प्रश्न
Solve the following problem :
Calculate Dorbish-Bowley’s Price Index Number for the following data.
| Commodity | Base Year | Current Year | ||
| Price p0 |
Quantity q0 |
Price p1 |
Quantity q1 |
|
| I | 8 | 30 | 11 | 28 |
| II | 9 | 25 | 12 | 22 |
| III | 10 | 15 | 13 | 11 |
Advertisements
उत्तर
| Commodity | Base Year | Current Year | p0q0 | p1q0 | p0q1 | p1q1 | ||
| p0 | q0 | p1 | q1 | |||||
| I | 8 | 30 | 11 | 28 | 240 | 330 | 224 | 308 |
| II | 9 | 25 | 12 | 22 | 225 | 300 | 198 | 264 |
| III | 10 | 15 | 13 | 11 | 150 | 195 | 110 | 143 |
| Total | – | – | – | – | 615 | 825 | 532 | 715 |
From the table,
`sum"p"_0"q"_0 = 615, sum"p"_1'q"_0 = 825`,
`sum"p"_0"q"_1 = 532, sum"p"_1"q"_1 = 715`
Dorbish-Bowley’s Price Index Number:
P01(D–B) = `((sum"p"_1"q"_0)/(sum"p"_0"q"_0) + (sum"p"_1"q"_1)/(sum"p"_0"q"_1))/(2) xx 100`
= `((825)/(615) + (715)/(532))/(2) xx 100`
= 134.27
APPEARS IN
संबंधित प्रश्न
Calculate Walsh’s Price Index Number.
| Commodity | Base Year | Current Year | ||
| Price | Quantity | Price | Quantity | |
| L | 4 | 16 | 3 | 19 |
| M | 6 | 16 | 8 | 14 |
| N | 8 | 28 | 7 | 32 |
Given that ∑p0q0 = 220, ∑p0q1 = 380, ∑p1q1 = 350 and Marshall-Edgeworth’s Price Index Number is 150, find Laspeyre’s Price Index Number.
If Dorbish-Bowley's and Fisher's Price Index Numbers are 5 and 4, respectively, then find Laspeyre's and Paasche's Price Index Numbers.
Choose the correct alternative :
Marshall-Edgeworth’s Price Index Number is given by
Choose the correct alternative :
Walsh’s Price Index Number is given by
Fill in the blank :
Paasche’s Price Index Number is given by _______.
Fill in the blank :
Marshall-Edgeworth’s Price Index Number is given by _______.
Walsh’s Price Index Number is given by _______.
State whether the following is True or False :
`(sum"p"_1"q"_0)/(sum"p"_0"q"_0) xx (sum"p"_1"q"_0)/(sum"p"_0"q"_0) xx 100` is Dorbish-Bowley’s Price Index Number.
`(sum"p"_0sqrt("q"_0"q"_1))/(sum"p"_1sqrt("q"_0"q"_1)) xx 100` is Walsh’s Price Index Number.
Solve the following problem :
Given that Laspeyre’s and Paasche’s Price Index Numbers are 25 and 16 respectively, find Dorbish-Bowley’s and Fisher’s Price Index Number.
Choose the correct alternative:
The formula P01 = `(sum"p"_1"q"_0)/(sum"p"_0"q"_0) xx 100` is for
Choose the correct alternative:
Walsh's Price Index Number is given by
The average of Laspeyre’s and Paasche’s Price Index Numbers is called ______ Price Index Number
State whether the following statement is True or False:
`(sum"p"_0sqrt("q"_0 + "q"_1))/(sum"p"_1sqrt("q"_0 + "q"_1)) xx 100` is Marshall-Edgeworth Price Index Number
Calculate Marshall-Edgeworth Price Index Number for following.
| Commodity | Base Year | Current Year | ||
| Price | Quantity | Price | Quantity | |
| A | 8 | 20 | 11 | 15 |
| B | 7 | 10 | 12 | 10 |
| C | 3 | 30 | 5 | 25 |
| D | 2 | 50 | 4 | 35 |
Calculate Walsh’s price Index Number for the following data.
| Commodity | Base Year | Current Year | ||
| Price | Quantity | Price | Quantity | |
| I | 10 | 12 | 40 | 3 |
| II | 20 | 2 | 25 | 8 |
| III | 30 | 3 | 50 | 27 |
| IV | 60 | 9 | 90 | 36 |
Find the missing price if Laspeyre’s and Paasche’s Price Index Numbers are equal for following data.
| Commodity | Base Year | Current Year | ||
| Price | Quantity | Price | Quantity | |
| A | 1 | 10 | 2 | 5 |
| B | 1 | 5 | – | 12 |
If `sum"p"_0"q"_0` = 150, `sum"p"_0"q"_1` = 250, `sum"p"_1"q"_1` = 375 and P01(L) = 140. Find P01(M-E)
If P01 (L) = 121, P01 (P) = 100, then P01 (F) = ______.
`sqrt((sump_1q_0)/(sump_0q_0)) xx sqrt((sump_1q_1)/(sump_0q_1)) xx 100`
Laspeyre’s Price Index Number uses current year’s quantities as weights.
If ∑ p0q0 = 120, ∑ p0q1 = 160, ∑ p1q1 = 140, ∑ p1qo = 200, find Laspeyre’s, Paasche’s, Dorbish-Bowley’s and Marshall-Edgeworth’s Price Index Numbers.
In the following table, Laspeyre's and Paasche's Price Index Numbers are equal. Complete the following activity to find x :
| Commodity | Base Year | Current year | ||
| Price | Quantity | Price | Quantity | |
| A | 2 | 10 | 2 | 5 |
| B | 2 | 5 | x | 2 |
Solution: P01(L) = P01(P)
`(sum "p"_1"q"_0)/(sum "p"_0"q"_0) xx 100 = square/(sum "p"_0"q"_1) xx 100`
`(20 + 5x)/square xx 100 = square/14 xx 100`
∴ x = `square`
