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For certain bivariate data the following information is available. For certain bivariate data the following information is available.

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प्रश्न

For certain bivariate data the following information is available.

  X Y
Mean 13 17
S.D. 3 2

Correlation coefficient between x and y is 0.6. estimate x when y = 15 and estimate y when x = 10.

योग
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उत्तर

Given, `bar x = 13, bar y = 1, sigma_"X" 3, sigma_"Y" = 2,` r = 0.6

`"b"_"YX" = "r" sigma_"Y"/sigma_"X" = 0.6 xx 2/3 = 0.4`

`"b"_"XY" = "r" sigma_"X"/sigma_"Y" = 0.6 xx 3/2 = 0.9`

The regression equation of X on Y is given by

`("X" - bar x) = "b"_"XY" ("Y" - bar y)`

(X - 13) = 0.9 (Y - 17)

X - 13 = 0.9Y - 15.3

X = 0.9Y - 15.3 + 13

X = - 2.3 + 0.9Y          ....(i)

For Y = 15, from equation (i) we get

X = - 2.3 + (0.9)(15) = - 2.3 + 13.5 = 11.2

The regression equation of Y on X is given by

`("Y" - bar y) = "b"_"YX" ("X" - bar x)`

(Y - 17) = 0.4(X - 13)

Y - 17 = 0.4X - 5.2

Y = 0.4X - 5.2 + 17

Y = 11.8 + 0.4X             .....(ii)

For X = 10, from equation (ii) we get

Y = 11.8 + 0.4(10) = 11.8 + 4 = 15.8

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Properties of Regression Coefficients
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Linear Regression - Exercise 3.2 [पृष्ठ ४८]

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बालभारती Mathematics and Statistics 2 (Commerce) [English] Standard 12 Maharashtra State Board
अध्याय 3 Linear Regression
Exercise 3.2 | Q 12 | पृष्ठ ४८

संबंधित प्रश्न

For bivariate data. `bar x = 53, bar y = 28, "b"_"YX" = - 1.2, "b"_"XY" = - 0.3` Find estimate of X for Y = 25.


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and 3x + 2y − 12 = 0 Find 

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x y `x - barx` `y - bary` `(x - barx)(y - bary)` `(x - barx)^2` `(y - bary)^2`
1 5 – 2 – 4 8 4 16
2 7 – 1 – 2 `square` 1 4
3 9 0 0 0 0 0
4 11 1 2 2 4 4
5 13 2 4 8 1 16
Total = 15 Total = 45 Total = 0 Total = 0 Total = `square` Total = 10 Total = 40

Mean of x = `barx = square`

Mean of y = `bary = square`

bxy = `square/square`

byx = `square/square`

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∴ Regression equation x on y is `square`

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∴ Regression equation of y on x is `square`


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Mean of y = 28

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`y - square = square (50 - square)`

∴ y = `square`

c. When y = 25,

`x - square = square (25 - square)`

∴ x = `square`


bXY . bYX = ______.


|bxy + byz| ≥ ______.


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