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Find the Value of X for Which the Points (X, −1), (2, 1) and (4, 5) Are Collinear.

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प्रश्न

Find the value of x for which the points (x, −1), (2, 1) and (4, 5) are collinear.

संक्षेप में उत्तर
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उत्तर

Let the given points be A (x, −1), B (2, 1) and C (4, 5).
Slope of AB =  \[\frac{1 + 1}{2 - x} = \frac{2}{2 - x}\]

Slope of BC = \[\frac{5 - 1}{4 - 2} = \frac{4}{2} = 2\]

It is given that the points (x, −1), (2, 1) and (4, 5) are collinear.

\[\therefore\] Slope of AB  = Slope of BC

\[\Rightarrow \frac{2}{2 - x} = 2\]

\[ \Rightarrow 1 = 2 - x\]

\[ \Rightarrow x = 1\]

Hence, the value of x is 1.

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अध्याय 23: The straight lines - Exercise 23.1 [पृष्ठ १४]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 23 The straight lines
Exercise 23.1 | Q 18 | पृष्ठ १४

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