हिंदी

Find the Value of X for Which the Points (X, −1), (2, 1) and (4, 5) Are Collinear. - Mathematics

Advertisements
Advertisements

प्रश्न

Find the value of x for which the points (x, −1), (2, 1) and (4, 5) are collinear.

संक्षेप में उत्तर
Advertisements

उत्तर

Let the given points be A (x, −1), B (2, 1) and C (4, 5).
Slope of AB =  \[\frac{1 + 1}{2 - x} = \frac{2}{2 - x}\]

Slope of BC = \[\frac{5 - 1}{4 - 2} = \frac{4}{2} = 2\]

It is given that the points (x, −1), (2, 1) and (4, 5) are collinear.

\[\therefore\] Slope of AB  = Slope of BC

\[\Rightarrow \frac{2}{2 - x} = 2\]

\[ \Rightarrow 1 = 2 - x\]

\[ \Rightarrow x = 1\]

Hence, the value of x is 1.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 23: The straight lines - Exercise 23.1 [पृष्ठ १४]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 11
अध्याय 23 The straight lines
Exercise 23.1 | Q 18 | पृष्ठ १४

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Without using distance formula, show that points (–2, –1), (4, 0), (3, 3) and (–3, 2) are vertices of a parallelogram.


A line passes through (x1, y1) and (h, k). If slope of the line is m, show that k – y1 = m (h – x1).


Find the values of k for which the line (k–3) x – (4 – k2) y + k2 –7k + 6 = 0 is 

  1. Parallel to the x-axis,
  2. Parallel to the y-axis,
  3. Passing through the origin.

Find the slope of the lines which make the following angle with the positive direction of x-axis:

\[\frac{2\pi}{3}\]


State whether the two lines in each of the following are parallel, perpendicular or neither.

Through (5, 6) and (2, 3); through (9, −2) and (6, −5)


State whether the two lines in each of the following is parallel, perpendicular or neither.

Through (3, 15) and (16, 6); through (−5, 3) and (8, 2).


Using the method of slope, show that the following points are collinear A (4, 8), B (5, 12), C (9, 28).


Line through the points (−2, 6) and (4, 8) is perpendicular to the line through the points (8, 12) and (x, 24). Find the value of x. 


By using the concept of slope, show that the points (−2, −1), (4, 0), (3, 3) and (−3, 2) are the vertices of a parallelogram.


Find the equation of a straight line with slope 2 and y-intercept 3 .


Find the equation of the strainght line intersecting y-axis at a distance of 2 units above the origin and making an angle of 30° with the positive direction of the x-axis.


Find the angles between the following pair of straight lines:

3x + y + 12 = 0 and x + 2y − 1 = 0


Find the angles between the following pair of straight lines:

3x + 4y − 7 = 0 and 4x − 3y + 5 = 0


Find the angles between the following pair of straight lines:

x − 4y = 3 and 6x − y = 11


Find the angle between the line joining the points (2, 0), (0, 3) and the line x + y = 1.


If θ is the angle which the straight line joining the points (x1, y1) and (x2, y2) subtends at the origin, prove that  \[\tan \theta = \frac{x_2 y_1 - x_1 y_2}{x_1 x_2 + y_1 y_2}\text { and } \cos \theta = \frac{x_1 x_2 + y_1 y_2}{\sqrt{{x_1}^2 + {y_1}^2}\sqrt{{x_2}^2 + {y_2}^2}}\].


Find the tangent of the angle between the lines which have intercepts 3, 4 and 1, 8 on the axes respectively.


Write the coordinates of the image of the point (3, 8) in the line x + 3y − 7 = 0.


The acute angle between the medians drawn from the acute angles of a right angled isosceles triangle is 


The angle between the lines 2x − y + 3 = 0 and x + 2y + 3 = 0 is


The reflection of the point (4, −13) about the line 5x + y + 6 = 0 is  


If m1 and m2 are slopes of lines represented by 6x2 - 5xy + y2 = 0, then (m1)3 + (m2)3 = ?


If x + y = k is normal to y2 = 12x, then k is ______.


Point of the curve y2 = 3(x – 2) at which the normal is parallel to the line 2y + 4x + 5 = 0 is ______.


If the line joining two points A(2, 0) and B(3, 1) is rotated about A in anticlock wise direction through an angle of 15°. Find the equation of the line in new position.


If one diagonal of a square is along the line 8x – 15y = 0 and one of its vertex is at (1, 2), then find the equation of sides of the square passing through this vertex.


The coordinates of the foot of the perpendicular from the point (2, 3) on the line x + y – 11 = 0 are ______.


The intercept cut off by a line from y-axis is twice than that from x-axis, and the line passes through the point (1, 2). The equation of the line is ______.


The reflection of the point (4, – 13) about the line 5x + y + 6 = 0 is ______.


Find the angle between the lines y = `(2 - sqrt(3)) (x + 5)` and y = `(2 + sqrt(3))(x - 7)`


Find the equation of one of the sides of an isosceles right angled triangle whose hypotenuse is given by 3x + 4y = 4 and the opposite vertex of the hypotenuse is (2, 2).


If the equation of the base of an equilateral triangle is x + y = 2 and the vertex is (2, – 1), then find the length of the side of the triangle.


If p is the length of perpendicular from the origin on the line `x/a + y/b` = 1 and a2, p2, b2 are in A.P, then show that a4 + b4 = 0.


If the vertices of a triangle have integral coordinates, then the triangle can not be equilateral.


The vertex of an equilateral triangle is (2, 3) and the equation of the opposite side is x + y = 2. Then the other two sides are y – 3 = `(2 +- sqrt(3)) (x - 2)`.


A ray of light coming from the point (1, 2) is reflected at a point A on the x-axis and then passes through the point (5, 3). The co-ordinates of the point A is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×