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Find the sum of first 24 terms of the A.P. a1, a2, a3, ... if it is known that a1 + a5 + a10 + a15 + a20 + a24 = 225. - Mathematics

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प्रश्न

Find the sum of first 24 terms of the A.P. a1, a2, a3, ... if it is known that a1 + a5 + a10 + a15 + a20 + a24 = 225.

योग
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उत्तर

We know that in an A.P., the sum of the terms equidistant from the beginning and end is always the same and is equal to the sum of first and last term.

Therefore d = b – a

i.e., a1 + a24 = a5 + a20

= a10 + a15

It is given that (a1 + a24) + (a5 + a20) + (a10 + a15) = 225

⇒ (a1 + a24) + (a1 + a24) + (a1 + a24) =225

⇒ 3(a1 + a24) = 225

⇒ a1 + a24 = 75

We know that Sn = `n/2[a + 1]`

Where a is the first term and l is the last term of an A.P.

Thus, S24 = `24/2 [a_1 + a_24]`

= 12 × 75

= 900

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अध्याय 9: Sequences and Series - Solved Examples [पृष्ठ १५२]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 9 Sequences and Series
Solved Examples | Q 5 | पृष्ठ १५२

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