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Find the absolute maximum value and the absolute minimum value of the following function in the given interval: f(x)=4x-1xx2,x∈[-2,92]

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प्रश्न

Find the absolute maximum value and the absolute minimum value of the following function in the given interval:

`f(x) = 4x - 1/x x^2, x in [-2 ,9/2]`

योग
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उत्तर

Given function f(x) = 4x `- 1/2 x^2,` interval `[-2,9/2]`

∴ f'(x) = 4 - `1/2`. 2x = 4 - x

If f'(x) = 0, then 4 - x = 0 ⇒ x = 4

At x = -2, f(-2) = 4 (-2) - `1/2 (-2)^2`

`= - 8 - 1/2 xx 4`

= - 8 - 2

= - 10

At x = 4, `f(4) = 4(4) - (4)^2/2`

`= 16 - 16/2`

= 16 - 8

= 8

At x = `9/2`, `f (9/2) = 4 xx 9/2 - 1/2 xx 81/4`

`= 18 - 81/8`

`= (144 - 81)/8`

`= 63/8`

= 7.875

∴ Absolute maximum value of f (x) = 8 at x = 4

Absolute minimum value of f (x) = -10 at x = -2

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अध्याय 6: Application of Derivatives - Exercise 6.5 [पृष्ठ २३२]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 6 Application of Derivatives
Exercise 6.5 | Q 4.3 | पृष्ठ २३२

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