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Find the maximum and minimum value, if any, of the following function given by h(x) = sin(2x) + 5.

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प्रश्न

Find the maximum and minimum value, if any, of the following function given by h(x) = sin(2x) + 5.

योग
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उत्तर

Given function h(x) = sin (2x) + 5

We know that -1 ≤ sin 2x ≤ 1

⇒ 4 ≤ 5 + sin 2x ≤ 6

Maximum value of sin 2x = 1

∴ h(x) = Maximum value of sin 2x + 5, 1 + 5 = 6

Minimum value of sin 2x = - 1

∴ h(x) = Minimum value of sin 2x + 5 = -1 + 5 = 4

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अध्याय 6: Application of Derivatives - Exercise 6.5 [पृष्ठ २३२]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 6 Application of Derivatives
Exercise 6.5 | Q 2.3 | पृष्ठ २३२

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