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What is the maximum value of the function sin x + cos x?

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प्रश्न

What is the maximum value of the function sin x + cos x?

योग
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उत्तर

Let f(x) = sin x + cos x, be the interval [0, 2π]

f'(x) = cos x - sin x

For the highest and lowest values,

f'(x) = 0  ⇒ cos x - sin x = 0 ⇒ tan x = 1

`therefore x = pi/4 , (5 pi)/4`

Putting the values ​​of x in f(x) = sin x + cos x, respectively,

At x = 0, f(0) = sin 0 + cos 0 = 1

x `= 2 pi  "at,"  f(2 pi) = sin 2 pi + cos 2 pi = 1`

x`= pi /4  "at,"  f(pi/4) = sin pi/4 + cos pi/4`

`= 1/sqrt2 + 1/sqrt2 = 2/sqrt2`

`= sqrt2`

x `= (5pi)/4  "at,"  f((5pi)/4) `

`= sin  (5 pi)/4 + cos  (5 pi)/4`

`= - 1/sqrt2 + 1/sqrt2`

`= - 2/sqrt2`

`= -sqrt2`

Hence, the highest value is at x = `pi/4` = `sqrt2`.

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अध्याय 6: Application of Derivatives - Exercise 6.5 [पृष्ठ २३२]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 6 Application of Derivatives
Exercise 6.5 | Q 9 | पृष्ठ २३२

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